Maximum current capability ratings are normally base on line voltage with maximum current ratings based on insulation temperature and ultimately wire size.
The reason you can use higher current at lower voltages is because wattage is a function of current times voltage. Thus wattage or power in the presence of changing voltage or current is used to rate wire capacity, still based on insulation temperature and ultimately wires size, i..e., wire diameter or crossection.
Ummm...NO, you can NOT use higher currents. The rotor resistance is constant, if we ignore the copper tempco, and the power dissipated in the winding resistance is the current squared times the resistance.
Dan
I am referring to published wire current ratings for line voltage. Wire rated at 10 amps at 120 volts can carry 20 amps at 60 volts, in terms of insulation temperature and ultimately wire size because the wattage is the same. Ignoring the differences for AC then:
1,200 watts = 10 amps x 120 volts
[1]...with the resistance of a conductor calculated as R= length of the conductor x electrical resistivity / cross sectional area.
[2]With AC voltages the
effective cross sectional area is reduced due to skin effect and is even lower for windings due to proximity effect.
Since 1,200 watts / 10 amps x 10 amps = 12 ohms and 120 volts
2 / 1,200 watts = 12 ohms and 60 volts
2 /12 ohms = 300 watts the following is correct:
300 watts is less than 1,200 watts such that the current can be raised by lowering the voltage to achieve the maximum current rating, since maximum current ratings are published for line voltage.
Since 300 watts,
is only a quarter of the 1.200 watts derived rating at 120 volts and 12 ohms, it is possible to double the current when cutting the voltage in half to achieve the maximum wattage.
References:
1Mathematics of electric power2Resistance of a conductor